Class Solution


  • public class Solution
    extends Object
    1005 - Maximize Sum Of Array After K Negations.

    Easy

    Given an integer array nums and an integer k, modify the array in the following way:

    • choose an index i and replace nums[i] with -nums[i].

    You should apply this process exactly k times. You may choose the same index i multiple times.

    Return the largest possible sum of the array after modifying it in this way.

    Example 1:

    Input: nums = [4,2,3], k = 1

    Output: 5

    Explanation: Choose index 1 and nums becomes [4,-2,3].

    Example 2:

    Input: nums = [3,-1,0,2], k = 3

    Output: 6

    Explanation: Choose indices (1, 2, 2) and nums becomes [3,1,0,2].

    Example 3:

    Input: nums = [2,-3,-1,5,-4], k = 2

    Output: 13

    Explanation: Choose indices (1, 4) and nums becomes [2,3,-1,5,4].

    Constraints:

    • 1 <= nums.length <= 104
    • -100 <= nums[i] <= 100
    • 1 <= k <= 104
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • largestSumAfterKNegations

        public int largestSumAfterKNegations​(int[] nums,
                                             int k)