Class Solution


  • public class Solution
    extends Object
    1178 - Number of Valid Words for Each Puzzle.

    Hard

    With respect to a given puzzle string, a word is valid if both the following conditions are satisfied:

    • word contains the first letter of puzzle.
    • For each letter in word, that letter is in puzzle.
      • For example, if the puzzle is "abcdefg", then valid words are "faced", "cabbage", and "baggage", while
      • invalid words are "beefed" (does not include 'a') and "based" (includes 's' which is not in the puzzle).

    Return an array answer, where answer[i] is the number of words in the given word list words that is valid with respect to the puzzle puzzles[i].

    Example 1:

    Input: words = [“aaaa”,“asas”,“able”,“ability”,“actt”,“actor”,“access”], puzzles = [“aboveyz”,“abrodyz”,“abslute”,“absoryz”,“actresz”,“gaswxyz”]

    Output: [1,1,3,2,4,0]

    Explanation:

    1 valid word for “aboveyz” : “aaaa”

    1 valid word for “abrodyz” : “aaaa”

    3 valid words for “abslute” : “aaaa”, “asas”, “able”

    2 valid words for “absoryz” : “aaaa”, “asas”

    4 valid words for “actresz” : “aaaa”, “asas”, “actt”, “access”

    There are no valid words for “gaswxyz” cause none of the words in the list contains letter ‘g’.

    Example 2:

    Input: words = [“apple”,“pleas”,“please”], puzzles = [“aelwxyz”,“aelpxyz”,“aelpsxy”,“saelpxy”,“xaelpsy”]

    Output: [0,1,3,2,0]

    Constraints:

    • 1 <= words.length <= 105
    • 4 <= words[i].length <= 50
    • 1 <= puzzles.length <= 104
    • puzzles[i].length == 7
    • words[i] and puzzles[i] consist of lowercase English letters.
    • Each puzzles[i] does not contain repeated characters.
    • Constructor Detail

      • Solution

        public Solution()