Class Solution
- java.lang.Object
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- g1101_1200.s1178_number_of_valid_words_for_each_puzzle.Solution
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public class Solution extends Object
1178 - Number of Valid Words for Each Puzzle.Hard
With respect to a given
puzzlestring, awordis valid if both the following conditions are satisfied:wordcontains the first letter ofpuzzle.- For each letter in
word, that letter is inpuzzle.- For example, if the puzzle is
"abcdefg", then valid words are"faced","cabbage", and"baggage", while - invalid words are
"beefed"(does not include'a') and"based"(includes's'which is not in the puzzle).
- For example, if the puzzle is
Return an array
answer, whereanswer[i]is the number of words in the given word listwordsthat is valid with respect to the puzzlepuzzles[i].Example 1:
Input: words = [“aaaa”,“asas”,“able”,“ability”,“actt”,“actor”,“access”], puzzles = [“aboveyz”,“abrodyz”,“abslute”,“absoryz”,“actresz”,“gaswxyz”]
Output: [1,1,3,2,4,0]
Explanation:
1 valid word for “aboveyz” : “aaaa”
1 valid word for “abrodyz” : “aaaa”
3 valid words for “abslute” : “aaaa”, “asas”, “able”
2 valid words for “absoryz” : “aaaa”, “asas”
4 valid words for “actresz” : “aaaa”, “asas”, “actt”, “access”
There are no valid words for “gaswxyz” cause none of the words in the list contains letter ‘g’.
Example 2:
Input: words = [“apple”,“pleas”,“please”], puzzles = [“aelwxyz”,“aelpxyz”,“aelpsxy”,“saelpxy”,“xaelpsy”]
Output: [0,1,3,2,0]
Constraints:
1 <= words.length <= 1054 <= words[i].length <= 501 <= puzzles.length <= 104puzzles[i].length == 7words[i]andpuzzles[i]consist of lowercase English letters.- Each
puzzles[i]does not contain repeated characters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description List<Integer>findNumOfValidWords(String[] words, String[] puzzles)
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