Class Solution


  • public class Solution
    extends Object
    1252 - Cells with Odd Values in a Matrix.

    Easy

    There is an m x n matrix that is initialized to all 0’s. There is also a 2D array indices where each indices[i] = [ri, ci] represents a 0-indexed location to perform some increment operations on the matrix.

    For each location indices[i], do both of the following:

    1. Increment all the cells on row ri.
    2. Increment all the cells on column ci.

    Given m, n, and indices, return the number of odd-valued cells in the matrix after applying the increment to all locations in indices.

    Example 1:

    Input: m = 2, n = 3, indices = [[0,1],[1,1]]

    Output: 6

    Explanation: Initial matrix = [[0,0,0],[0,0,0]].

    After applying first increment it becomes [[1,2,1],[0,1,0]].

    The final matrix is [[1,3,1],[1,3,1]], which contains 6 odd numbers.

    Example 2:

    Input: m = 2, n = 2, indices = [[1,1],[0,0]]

    Output: 0

    Explanation: Final matrix = [[2,2],[2,2]]. There are no odd numbers in the final matrix.

    Constraints:

    • 1 <= m, n <= 50
    • 1 <= indices.length <= 100
    • 0 <= ri < m
    • 0 <= ci < n

    Follow up: Could you solve this in O(n + m + indices.length) time with only O(n + m) extra space?

    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • oddCells

        public int oddCells​(int n,
                            int m,
                            int[][] indices)