Class Solution


  • public class Solution
    extends Object
    1432 - Max Difference You Can Get From Changing an Integer.

    Medium

    You are given an integer num. You will apply the following steps exactly two times:

    • Pick a digit x (0 <= x <= 9).
    • Pick another digit y (0 <= y <= 9). The digit y can be equal to x.
    • Replace all the occurrences of x in the decimal representation of num by y.
    • The new integer cannot have any leading zeros, also the new integer cannot be 0.

    Let a and b be the results of applying the operations to num the first and second times, respectively.

    Return the max difference between a and b.

    Example 1:

    Input: num = 555

    Output: 888

    Explanation: The first time pick x = 5 and y = 9 and store the new integer in a.

    The second time pick x = 5 and y = 1 and store the new integer in b.

    We have now a = 999 and b = 111 and max difference = 888

    Example 2:

    Input: num = 9

    Output: 8

    Explanation: The first time pick x = 9 and y = 9 and store the new integer in a.

    The second time pick x = 9 and y = 1 and store the new integer in b.

    We have now a = 9 and b = 1 and max difference = 8

    Constraints:

    • 1 <= num <= 108
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxDiff

        public int maxDiff​(int num)