Class Solution


  • public class Solution
    extends Object
    1433 - Check If a String Can Break Another String.

    Medium

    Given two strings: s1 and s2 with the same size, check if some permutation of string s1 can break some permutation of string s2 or vice-versa. In other words s2 can break s1 or vice-versa.

    A string x can break string y (both of size n) if x[i] >= y[i] (in alphabetical order) for all i between 0 and n-1.

    Example 1:

    Input: s1 = “abc”, s2 = “xya”

    Output: true

    Explanation: “ayx” is a permutation of s2=“xya” which can break to string “abc” which is a permutation of s1=“abc”.

    Example 2:

    Input: s1 = “abe”, s2 = “acd”

    Output: false

    Explanation: All permutations for s1=“abe” are: “abe”, “aeb”, “bae”, “bea”, “eab” and “eba” and all permutation for s2=“acd” are: “acd”, “adc”, “cad”, “cda”, “dac” and “dca”. However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.

    Example 3:

    Input: s1 = “leetcodee”, s2 = “interview”

    Output: true

    Constraints:

    • s1.length == n
    • s2.length == n
    • 1 <= n <= 10^5
    • All strings consist of lowercase English letters.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • checkIfCanBreak

        public boolean checkIfCanBreak​(String s1,
                                       String s2)