Class Solution
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- g1501_1600.s1557_minimum_number_of_vertices_to_reach_all_nodes.Solution
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public class Solution extends Object
1557 - Minimum Number of Vertices to Reach All Nodes.Medium
Given a** directed acyclic graph** , with
nvertices numbered from0ton-1, and an arrayedgeswhereedges[i] = [fromi, toi]represents a directed edge from nodefromito nodetoi.Find the smallest set of vertices from which all nodes in the graph are reachable. It’s guaranteed that a unique solution exists.
Notice that you can return the vertices in any order.
Example 1:

Input: n = 6, edges = [[0,1],[0,2],[2,5],[3,4],[4,2]]
Output: [0,3]
Explanation: It’s not possible to reach all the nodes from a single vertex. From 0 we can reach [0,1,2,5]. From 3 we can reach [3,4,2,5]. So we output [0,3].
Example 2:

Input: n = 5, edges = [[0,1],[2,1],[3,1],[1,4],[2,4]]
Output: [0,2,3]
Explanation: Notice that vertices 0, 3 and 2 are not reachable from any other node, so we must include them. Also any of these vertices can reach nodes 1 and 4.
Constraints:
2 <= n <= 10^51 <= edges.length <= min(10^5, n * (n - 1) / 2)edges[i].length == 20 <= fromi, toi < n- All pairs
(fromi, toi)are distinct.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description List<Integer>findSmallestSetOfVertices(int n, List<List<Integer>> edges)
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