Solution (leetcode-in-java 1.21 API)

java.lang.Object
- g1901_2000.s1941_check_if_all_characters_have_equal_number_of_occurrences.Solution

```
public class Solution
extends Object
```
1941 - Check if All Characters Have Equal Number of Occurrences.
Easy

Given a string s, return true if s is a good string, or false otherwise.

A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).

Example 1:

Input: s = “abacbc”

Output: true

Explanation: The characters that appear in s are ‘a’, ‘b’, and ‘c’. All characters occur 2 times in s.

Example 2:

Input: s = “aaabb”

Output: false

Explanation: The characters that appear in s are ‘a’ and ‘b’. ‘a’ occurs 3 times while ‘b’ occurs 2 times, which is not the same number of times.

Constraints:
- 1 <= s.length <= 1000
- s consists of lowercase English letters.

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  boolean areOccurrencesEqual(String s)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

areOccurrencesEqual

public boolean areOccurrencesEqual(String s)