Package g2001_2100.s2011_final_value_of_variable_after_performing_operations

Class Solution

  • public class Solution
extends Object
    2011 - Final Value of Variable After Performing Operations.

    Easy

    There is a programming language with only four operations and one variable X:

    • ++X and X++ increments the value of the variable X by 1.
    • --X and X-- decrements the value of the variable X by 1.

    Initially, the value of X is 0.

    Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

    Example 1:

    Input: operations = [“–X”,“X++”,“X++”]

    Output: 1

    Explanation: The operations are performed as follows:

    Initially, X = 0.

    –X: X is decremented by 1, X = 0 - 1 = -1.

    X++: X is incremented by 1, X = -1 + 1 = 0.

    X++: X is incremented by 1, X = 0 + 1 = 1.

    Example 2:

    Input: operations = [“++X”,“++X”,“X++”]

    Output: 3

    Explanation: The operations are performed as follows:

    Initially, X = 0.

    ++X: X is incremented by 1, X = 0 + 1 = 1.

    ++X: X is incremented by 1, X = 1 + 1 = 2.

    X++: X is incremented by 1, X = 2 + 1 = 3.

    Example 3:

    Input: operations = [“X++”,“++X”,“–X”,“X–”]

    Output: 0

    Explanation: The operations are performed as follows:

    Initially, X = 0.

    X++: X is incremented by 1, X = 0 + 1 = 1.

    ++X: X is incremented by 1, X = 1 + 1 = 2.

    –X: X is decremented by 1, X = 2 - 1 = 1.

    X–: X is decremented by 1, X = 1 - 1 = 0.

    Constraints:

    • 1 <= operations.length <= 100
    • operations[i] will be either "++X", "X++", "--X", or "X--".

    • Constructor Detail

      • Solution

        public Solution()

    • Method Detail

      • finalValueAfterOperations

        public int finalValueAfterOperations​(String[] operations)