Package g2001_2100.s2018_check_if_word_can_be_placed_in_crossword

Class Solution

  • public class Solution
extends Object
    2018 - Check if Word Can Be Placed In Crossword.

    Medium

    You are given an m x n matrix board, representing the current state of a crossword puzzle. The crossword contains lowercase English letters (from solved words), ' ' to represent any empty cells, and '#' to represent any blocked cells.

    A word can be placed horizontally (left to right or right to left) or vertically (top to bottom or bottom to top) in the board if:

    • It does not occupy a cell containing the character '#'.
    • The cell each letter is placed in must either be ' ' (empty) or match the letter already on the board.
    • There must not be any empty cells ' ' or other lowercase letters directly left or right of the word if the word was placed horizontally.
    • There must not be any empty cells ' ' or other lowercase letters directly above or below the word if the word was placed vertically.

    Given a string word, return true if word can be placed in board, or false otherwise.

    Example 1:

    Input: board = [[“#”, " ", “#”], [" ", " ", “#”], [“#”, “c”, " "]], word = “abc”

    Output: true

    Explanation: The word “abc” can be placed as shown above (top to bottom).

    Example 2:

    Input: board = [[" ", “#”, “a”], [" ", “#”, “c”], [" ", “#”, “a”]], word = “ac”

    Output: false

    Explanation: It is impossible to place the word because there will always be a space/letter above or below it.

    Example 3:

    Input: board = [[“#”, " ", “#”], [" ", " ", “#”], [“#”, " ", “c”]], word = “ca”

    Output: true

    Explanation: The word “ca” can be placed as shown above (right to left).

    Constraints:

    • m == board.length
    • n == board[i].length
    • 1 <= m * n <= 2 * 105
    • board[i][j] will be ' ', '#', or a lowercase English letter.
    • 1 <= word.length <= max(m, n)
    • word will contain only lowercase English letters.

    • Constructor Detail

      • Solution

        public Solution()

    • Method Detail

      • placeWordInCrossword

        public boolean placeWordInCrossword​(char[][] board,
                                    String word)