Class Solution


  • public class Solution
    extends Object
    2078 - Two Furthest Houses With Different Colors.

    Easy

    There are n houses evenly lined up on the street, and each house is beautifully painted. You are given a 0-indexed integer array colors of length n, where colors[i] represents the color of the ith house.

    Return the maximum distance between two houses with different colors.

    The distance between the ith and jth houses is abs(i - j), where abs(x) is the absolute value of x.

    Example 1:

    Input: colors = [1 ,1,1, 6 ,1,1,1]

    Output: 3

    Explanation: In the above image, color 1 is blue, and color 6 is red.

    The furthest two houses with different colors are house 0 and house 3.

    House 0 has color 1, and house 3 has color 6.

    The distance between them is abs(0 - 3) = 3.

    Note that houses 3 and 6 can also produce the optimal answer.

    Example 2:

    Input: colors = [1 ,8,3,8, 3 ]

    Output: 4

    Explanation: In the above image, color 1 is blue, color 8 is yellow, and color 3 is green.

    The furthest two houses with different colors are house 0 and house 4.

    House 0 has color 1, and house 4 has color 3.

    The distance between them is abs(0 - 4) = 4.

    Example 3:

    Input: colors = [0 , 1 ]

    Output: 1

    Explanation: The furthest two houses with different colors are house 0 and house 1.

    House 0 has color 0, and house 1 has color 1.

    The distance between them is abs(0 - 1) = 1.

    Constraints:

    • n == colors.length
    • 2 <= n <= 100
    • 0 <= colors[i] <= 100
    • Test data are generated such that at least two houses have different colors.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxDistance

        public int maxDistance​(int[] colors)