Class Solution
- java.lang.Object
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- g2401_2500.s2416_sum_of_prefix_scores_of_strings.Solution
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public class Solution extends Object
2416 - Sum of Prefix Scores of Strings.Hard
You are given an array
wordsof sizenconsisting of non-empty strings.We define the score of a string
wordas the number of stringswords[i]such thatwordis a prefix ofwords[i].- For example, if
words = ["a", "ab", "abc", "cab"], then the score of"ab"is2, since"ab"is a prefix of both"ab"and"abc".
Return an array
answerof sizenwhereanswer[i]is the sum of scores of every non-empty prefix ofwords[i].Note that a string is considered as a prefix of itself.
Example 1:
Input: words = [“abc”,“ab”,“bc”,“b”]
Output: [5,4,3,2]
Explanation: The answer for each string is the following:
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“abc” has 3 prefixes: “a”, “ab”, and “abc”.
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There are 2 strings with the prefix “a”, 2 strings with the prefix “ab”, and 1 string with the prefix “abc”.
The total is answer[0] = 2 + 2 + 1 = 5.
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“ab” has 2 prefixes: “a” and “ab”.
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There are 2 strings with the prefix “a”, and 2 strings with the prefix “ab”.
The total is answer[1] = 2 + 2 = 4.
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“bc” has 2 prefixes: “b” and “bc”.
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There are 2 strings with the prefix “b”, and 1 string with the prefix “bc”.
The total is answer[2] = 2 + 1 = 3.
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“b” has 1 prefix: “b”.
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There are 2 strings with the prefix “b”.
The total is answer[3] = 2.
Example 2:
Input: words = [“abcd”]
Output: [4]
Explanation:
“abcd” has 4 prefixes: “a”, “ab”, “abc”, and “abcd”.
Each prefix has a score of one, so the total is answer[0] = 1 + 1 + 1 + 1 = 4.
Constraints:
1 <= words.length <= 10001 <= words[i].length <= 1000words[i]consists of lowercase English letters.
- For example, if
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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sumPrefixScores
public int[] sumPrefixScores(String[] words)
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